Optimal. Leaf size=161 \[ -\frac{x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac{a C}{c}+A\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}-\frac{2 \left (C \left (2 a c+b^2\right )+6 A c^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{5/2}}+\frac{(b+2 c x) \left (2 a C+6 A c+\frac{b^2 C}{c}\right )}{2 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )} \]
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Rubi [A] time = 0.113923, antiderivative size = 161, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {1660, 12, 614, 618, 206} \[ -\frac{x \left (C \left (b^2-2 a c\right )+2 A c^2\right )+b c \left (\frac{a C}{c}+A\right )}{2 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}-\frac{2 \left (C \left (2 a c+b^2\right )+6 A c^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{5/2}}+\frac{(b+2 c x) \left (2 a C+6 A c+\frac{b^2 C}{c}\right )}{2 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )} \]
Antiderivative was successfully verified.
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Rule 1660
Rule 12
Rule 614
Rule 618
Rule 206
Rubi steps
\begin{align*} \int \frac{A+C x^2}{\left (a+b x+c x^2\right )^3} \, dx &=-\frac{b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x}{2 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}-\frac{\int \frac{6 A c+2 a C+\frac{b^2 C}{c}}{\left (a+b x+c x^2\right )^2} \, dx}{2 \left (b^2-4 a c\right )}\\ &=-\frac{b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x}{2 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}-\frac{\left (6 A c+2 a C+\frac{b^2 C}{c}\right ) \int \frac{1}{\left (a+b x+c x^2\right )^2} \, dx}{2 \left (b^2-4 a c\right )}\\ &=-\frac{b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x}{2 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}+\frac{\left (6 A c+2 a C+\frac{b^2 C}{c}\right ) (b+2 c x)}{2 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )}+\frac{\left (6 A c^2+\left (b^2+2 a c\right ) C\right ) \int \frac{1}{a+b x+c x^2} \, dx}{\left (b^2-4 a c\right )^2}\\ &=-\frac{b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x}{2 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}+\frac{\left (6 A c+2 a C+\frac{b^2 C}{c}\right ) (b+2 c x)}{2 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )}-\frac{\left (2 \left (6 A c^2+\left (b^2+2 a c\right ) C\right )\right ) \operatorname{Subst}\left (\int \frac{1}{b^2-4 a c-x^2} \, dx,x,b+2 c x\right )}{\left (b^2-4 a c\right )^2}\\ &=-\frac{b c \left (A+\frac{a C}{c}\right )+\left (2 A c^2+\left (b^2-2 a c\right ) C\right ) x}{2 c \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2}+\frac{\left (6 A c+2 a C+\frac{b^2 C}{c}\right ) (b+2 c x)}{2 \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )}-\frac{2 \left (6 A c^2+\left (b^2+2 a c\right ) C\right ) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{\left (b^2-4 a c\right )^{5/2}}\\ \end{align*}
Mathematica [A] time = 0.220095, size = 160, normalized size = 0.99 \[ \frac{1}{2} \left (\frac{(b+2 c x) \left (C \left (2 a c+b^2\right )+6 A c^2\right )}{c \left (b^2-4 a c\right )^2 (a+x (b+c x))}+\frac{4 \left (C \left (2 a c+b^2\right )+6 A c^2\right ) \tan ^{-1}\left (\frac{b+2 c x}{\sqrt{4 a c-b^2}}\right )}{\left (4 a c-b^2\right )^{5/2}}+\frac{a C (b-2 c x)+A c (b+2 c x)+b^2 C x}{c \left (4 a c-b^2\right ) (a+x (b+c x))^2}\right ) \]
Antiderivative was successfully verified.
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Maple [B] time = 0.183, size = 373, normalized size = 2.3 \begin{align*}{\frac{1}{ \left ( c{x}^{2}+bx+a \right ) ^{2}} \left ({\frac{c \left ( 6\,A{c}^{2}+2\,Cac+C{b}^{2} \right ){x}^{3}}{16\,{a}^{2}{c}^{2}-8\,ac{b}^{2}+{b}^{4}}}+{\frac{3\,b \left ( 6\,A{c}^{2}+2\,Cac+C{b}^{2} \right ){x}^{2}}{32\,{a}^{2}{c}^{2}-16\,ac{b}^{2}+2\,{b}^{4}}}+{\frac{ \left ( 10\,aA{c}^{2}+2\,A{b}^{2}c-2\,C{a}^{2}c+5\,Ca{b}^{2} \right ) x}{16\,{a}^{2}{c}^{2}-8\,ac{b}^{2}+{b}^{4}}}+{\frac{b \left ( 10\,aAc-A{b}^{2}+6\,{a}^{2}C \right ) }{32\,{a}^{2}{c}^{2}-16\,ac{b}^{2}+2\,{b}^{4}}} \right ) }+12\,{\frac{A{c}^{2}}{ \left ( 16\,{a}^{2}{c}^{2}-8\,ac{b}^{2}+{b}^{4} \right ) \sqrt{4\,ac-{b}^{2}}}\arctan \left ({\frac{2\,cx+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) }+4\,{\frac{Cac}{ \left ( 16\,{a}^{2}{c}^{2}-8\,ac{b}^{2}+{b}^{4} \right ) \sqrt{4\,ac-{b}^{2}}}\arctan \left ({\frac{2\,cx+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) }+2\,{\frac{C{b}^{2}}{ \left ( 16\,{a}^{2}{c}^{2}-8\,ac{b}^{2}+{b}^{4} \right ) \sqrt{4\,ac-{b}^{2}}}\arctan \left ({\frac{2\,cx+b}{\sqrt{4\,ac-{b}^{2}}}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.73505, size = 2592, normalized size = 16.1 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [B] time = 2.6655, size = 774, normalized size = 4.81 \begin{align*} - \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) \log{\left (x + \frac{6 A b c^{2} + 2 C a b c + C b^{3} - 64 a^{3} c^{3} \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) + 48 a^{2} b^{2} c^{2} \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) - 12 a b^{4} c \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) + b^{6} \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right )}{12 A c^{3} + 4 C a c^{2} + 2 C b^{2} c} \right )} + \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) \log{\left (x + \frac{6 A b c^{2} + 2 C a b c + C b^{3} + 64 a^{3} c^{3} \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) - 48 a^{2} b^{2} c^{2} \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) + 12 a b^{4} c \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right ) - b^{6} \sqrt{- \frac{1}{\left (4 a c - b^{2}\right )^{5}}} \left (6 A c^{2} + 2 C a c + C b^{2}\right )}{12 A c^{3} + 4 C a c^{2} + 2 C b^{2} c} \right )} + \frac{10 A a b c - A b^{3} + 6 C a^{2} b + x^{3} \left (12 A c^{3} + 4 C a c^{2} + 2 C b^{2} c\right ) + x^{2} \left (18 A b c^{2} + 6 C a b c + 3 C b^{3}\right ) + x \left (20 A a c^{2} + 4 A b^{2} c - 4 C a^{2} c + 10 C a b^{2}\right )}{32 a^{4} c^{2} - 16 a^{3} b^{2} c + 2 a^{2} b^{4} + x^{4} \left (32 a^{2} c^{4} - 16 a b^{2} c^{3} + 2 b^{4} c^{2}\right ) + x^{3} \left (64 a^{2} b c^{3} - 32 a b^{3} c^{2} + 4 b^{5} c\right ) + x^{2} \left (64 a^{3} c^{3} - 12 a b^{4} c + 2 b^{6}\right ) + x \left (64 a^{3} b c^{2} - 32 a^{2} b^{3} c + 4 a b^{5}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.27177, size = 293, normalized size = 1.82 \begin{align*} \frac{2 \,{\left (C b^{2} + 2 \, C a c + 6 \, A c^{2}\right )} \arctan \left (\frac{2 \, c x + b}{\sqrt{-b^{2} + 4 \, a c}}\right )}{{\left (b^{4} - 8 \, a b^{2} c + 16 \, a^{2} c^{2}\right )} \sqrt{-b^{2} + 4 \, a c}} + \frac{2 \, C b^{2} c x^{3} + 4 \, C a c^{2} x^{3} + 12 \, A c^{3} x^{3} + 3 \, C b^{3} x^{2} + 6 \, C a b c x^{2} + 18 \, A b c^{2} x^{2} + 10 \, C a b^{2} x - 4 \, C a^{2} c x + 4 \, A b^{2} c x + 20 \, A a c^{2} x + 6 \, C a^{2} b - A b^{3} + 10 \, A a b c}{2 \,{\left (b^{4} - 8 \, a b^{2} c + 16 \, a^{2} c^{2}\right )}{\left (c x^{2} + b x + a\right )}^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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